(2x^2-7x+3)/(x^2+x-12)

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Solution for (2x^2-7x+3)/(x^2+x-12) equation: 


D( x )

x^2+x-12 = 0

x^2+x-12 = 0

x^2+x-12 = 0

x^2+x-12 = 0

DELTA = 1^2-(-12*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-1)/(1*2) or x = (-49^(1/2)-1)/(1*2)

x = 3 or x = -4

x in (-oo:-4) U (-4:3) U (3:+oo)

(2*x^2-(7*x)+3)/(x^2+x-12) = 0

(2*x^2-7*x+3)/(x^2+x-12) = 0

2*x^2-7*x+3 = 0

2*x^2-7*x+3 = 0

DELTA = (-7)^2-(2*3*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+7)/(2*2) or x = (7-25^(1/2))/(2*2)

x = 3 or x = 1/2

(x-1/2)*(x-3) = 0

x^2+x-12 = 0

x^2+x-12 = 0

DELTA = 1^2-(-12*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-1)/(1*2) or x = (-49^(1/2)-1)/(1*2)

x = 3 or x = -4

(x+4)*(x-3) = 0

((x-1/2)*(x-3))/((x+4)*(x-3)) = 0

( x-1/2 )

x-1/2 = 0 // + 1/2

x = 1/2

( x-3 )

x-3 = 0 // + 3

x = 3

x in { 3} 

x = 1/2

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